Post marked as solved
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Views
override func viewDidAppear(_ animated: Bool) {
super.viewDidAppear(animated)
for percent in 1...10 {
print(percent)
self.accuracyLabel.text = "\(percent)" + "%"
sleep(UInt32(0.9))
}
}
@IBOutlet weak var accuracyLabel: UILabel!
Hi,
I have 2 problems with this code:
1) sleep(UInt32(1.0)) correctly prints 'percent' every 1 second.
But as soon as I go under 1.0, such as sleep(UInt32(0.9)), the print don't happen every 0.9 seconds, but instantly. Why is that?
2) @IBOutlet weak var accuracyLabel: UILabel! text is not updated on each iteration, but only after entire loop has completed. This is not what I would have expected, I would have expected update on each iteration, why is it not the case?
regards,
Brak
Post marked as solved
37
Views
Hi,
I need to move the controller up so fields are not hidden by keyboard.
So I use textfield and textview delegate methods to achieve this.
Here is the code, but it is repetitive.
Is there any way to make it less repetitive?
func textFieldDidBeginEditing(_ textField: UITextField) {
self.view.setNeedsLayout()
UIView.animate(withDuration: 0.2, animations: {
self.view.center.y -= 150
}, completion: { finished in
})
}
func textFieldDidEndEditing(_ textField: UITextField) {
self.view.setNeedsLayout()
UIView.animate(withDuration: 0.2, animations: {
self.view.center.y += 150
}, completion: { finished in
})
}
func textViewDidBeginEditing(_ textField: UITextView) {
self.view.setNeedsLayout()
UIView.animate(withDuration: 0.2, animations: {
self.view.center.y -= 150
}, completion: { finished in
})
}
func textViewDidEndEditing(_ textField: UITextView) {
self.view.setNeedsLayout()
UIView.animate(withDuration: 0.2, animations: {
self.view.center.y += 150
}, completion: { finished in
})
}
Post marked as unsolved
58
Views
Hi,
down there you will find an implementation of the coreML/squeeze net that prints first prediction and confidence level.
Problem is that its prediction are not general enough: if I send it a dog, it will try to guess the dog breed, instead of general categorization of "Dog" or even "Animal".
Is there anyway to ask the model to return broader category?
static func analyzeImageMl(image: UIImage) {
if let imageToParse = image.cgImage {
do {
let model = try SqueezeNet(configuration: MLModelConfiguration())
let mlModel = model.model
do {
let visionModel = try VNCoreMLModel(for: mlModel)
let request = VNCoreMLRequest(model: visionModel) { (response, error) in
if let e = error {
print("Error is: \(e.localizedDescription)")
}
if let r = response.results as? [VNClassificationObservation] {
if let f = r.first {
let id = f.identifier
let confidenceToPercent = f.confidence * 100
let confidenceString = String(format: "%.2f", confidenceToPercent)
print("I think this object is: \(id)\n with a confidence of: \(confidenceString)%")
}
}
}
let handler = VNImageRequestHandler(cgImage: imageToParse, options: [:])
try handler.perform([request])
} catch {
print(error.localizedDescription)
}
} catch {
print(error.localizedDescription)
}
}
}
Post marked as solved
53
Views
Hi here is the code:
let button = self.votingButtonsContainer[0]
let layer = button.layer
let rotationAngle: CGFloat = 49
var rotationAndPerspectiveTransform = CATransform3DIdentity
rotationAndPerspectiveTransform.m34 = 1.0 / -500
rotationAndPerspectiveTransform = CATransform3DRotate(rotationAndPerspectiveTransform, rotationAngle * .pi / 180.0, 0.0, 1.0, 0.0)
layer.transform = rotationAndPerspectiveTransform
This code correctly rotate in 3D my "button" in this case by 49 degrees (rotationAngle).
Problem is that this is not animated.
How to make this code animate the rotation, instead of simply displaying the result?
Post marked as unsolved
74
Views
Hi,
my native iOS app requires user to be logged in to use its features.
I implemented a clean and neat sign it with apple.
Is it even worth bothering implementing other signs in, like fb, or google?
This message is for people using apple sign in as well as other sign in methods, if you could share your rough % of sign in distribution.
Thanks,
Ald
Post marked as solved
46
Views
This code is invalid:
func name1() {
func nest1() - Int {
print("nest1")
return 3
}
func nest1() - String {
print("nest2")
return "nest1"
}
}
both nest1 function can't coexist.
But they have a different signature: one is returning an int and the other a string.
Aren't functions with different signatures, supposed to be able to coexist?
Post marked as solved
33
Views
class One {
func sayOne() {
print("from inside One")
}
class Second {
func saySecond() {
print("from inside second")
}
}
}
One.Second().saySecond()
Why can I access Second class without instantiating One() with parenthesis, when I can't access member function and variables without instantiation with ()?
Post marked as unsolved
154
Views
I'm building a quiz system and i'm not sure how to structure it on the database side.Let's say the quiz system is for trees species. User will be presented a tree picture (an entry), and will have to select the correct species among a list of 6 (5 random, 1 correct). There are 250 species in the quiz.The two main problems I need to solve:1) User should never see again the same tree entry.2) Owner of a tree entry, must be able to see stats of all the votes on his entry: so he will see number of votes, per tree species, entered by other users on his entry. Because users will make mistakes on votes, owner of entry will see stats of those mistakes and which incorrect species his entry was mistaken for.An easy way to do it, would be to create several tables:Users tableTrees table: With foreign key to User table. This is entries users will have to vote on. One user can create one entry.Votes tables: With foreign key to both user table and tree table. This table will hold each and every vote, including tree species name selected by the user on that vote.So to solve my problem:1) Prevent user to see same entry again: Before fetching "Trees" to present new trees to vote on, run a first query to get all "Votes" for that user to exclude "Trees" the user has already voted on.2) See stats of votes on own entry: Fetch all votes pointing to own entry, then compute stats by tree species selected.This approach is straightforward, but what bothers me is having to create an entry for each and every vote. There can be lots of it. I'm inexperienced with db design, so not sure if this could be a problem or not.Would this alternative way be better:1) To keep track of already voted entries: On a single record (per user), hold in a single field, ALL voted ids, so instead of running a query to prefetch each votes entries, simply get them from a single field. Not sure if this is doable, and what is the limit size of a single field that could potentially hold thousands of votes which are in fact ids of entries voted on.2) So owner of an entry can view that entry statistics: On EACH tree entry, create 250 columns, one per tree species, and increment an INT on each depending on what is voted on. So to get stats of each entry, it would only be a matter of fetching one single record and do the computation client side.What would be the best approach? Is there one that should be avoided?
Post marked as unsolved
322
Views
Hello,I have a web app (not a content website wrapped into an app - a game) based purely on web technologies: html5 + js + css.Are there any chances for a web app compiled with PhoneGap to pass the review process and be distributed on the app store? Is it even worth trying?Do you have examples?Cordially,Aldar
Post marked as unsolved
455
Views
Hello,is it possible for an app accepted in the expedited review queue to take 24 hours or more to be "in review" ?From my experience it usually take a few hours, but this time it seems it takes much more.What's your experience ?Cordially,Aldar
